Question

Consider the chemical reaction A(g) + B(g) ↔ 2C(g). At equilibrium, the concentration of A is 0.25 M, the concentration of B is 0.15 M, and the concentration of C is 0.40 M. What is the equilibrium constant for this reaction at the given temperature?

Answer 1

To find the equilibrium constant  Kc  for the given reaction, we can use the expression:Kc = [C]^2 /  [A] * [B] At equilibrium, the concentrations are given as [A] = 0.25 M, [B] = 0.15 M, and [C] = 0.40 M. Plugging these values into the expression, we get:Kc =  0.40 ^2 /  0.25 * 0.15 Kc = 0.16 / 0.0375Kc  4.27So, the equilibrium constant for this reaction at the given temperature is approximately 4.27.