Question

Calculate the equilibrium constant (Kc) for the following chemical reaction at 25°C, given that the concentrations of reactant A and product B are 0.05 M and 0.10 M, respectively:A(s) + 2B(g) ⇌ 3C(g) The equilibrium concentration of compound C is found to be 0.15 M.

Answer 1

To calculate the equilibrium constant  Kc  for the given reaction, we first need to write the expression for Kc. For the reaction:A s  + 2B g   3C g The Kc expression is:Kc = [C]^3 / [B]^2Since A is a solid, it is not included in the Kc expression.Now, we are given the equilibrium concentrations of B and C:[B] = 0.10 M[C] = 0.15 MPlug these values into the Kc expression:Kc =  0.15 ^3 /  0.10 ^2Kc =  0.003375  /  0.01 Kc = 0.3375Therefore, the equilibrium constant  Kc  for the given reaction at 25C is 0.3375.