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Calculate the surface tension of water at a temperature of 25°C using the capillary rise method, given that the diameter of the capillary tube is 0.8 mm and the rise of water in the tube is 3 cm.

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ago by (510 points)
To calculate the surface tension of water using the capillary rise method, we can use the Jurin's Law formula:h =  2 *  * cos  /   * g * r where:h = capillary rise  height of the liquid column  = 3 cm = 0.03 m = surface tension  what we want to find  = contact angle between the liquid and the capillary tube  for water, it is approximately 0, so cos = 1  = density of the liquid  for water at 25C, it is approximately 997 kg/m g = acceleration due to gravity  approximately 9.81 m/s r = radius of the capillary tube  diameter is 0.8 mm, so radius is 0.4 mm = 0.0004 m Rearranging the formula to solve for : =   * g * r * h  /  2 * cos Plugging in the values: =  997 kg/m * 9.81 m/s * 0.0004 m * 0.03 m  /  2 * 1  =  0.117 kg * m/s  / 2 = 0.0585 kg * m/sSo, the surface tension of water at 25C is approximately 0.0585 N/m  Newtons per meter .

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