To calculate the standard enthalpy change for the sublimation of iodine at 25C, we need to consider the two processes involved in sublimation: fusion melting and vaporization. The enthalpy change for sublimation is the sum of the enthalpy changes for these two processes.H_sublimation = H_fusion + H_vaporizationGiven that the standard enthalpy of fusion of iodine is 15.7 kJ/mol and the standard enthalpy of vaporization of iodine is 41.0 kJ/mol, we can plug these values into the equation:H_sublimation = 15.7 kJ/mol + 41.0 kJ/molH_sublimation = 56.7 kJ/molTherefore, the standard enthalpy change for the sublimation of iodine at 25C is 56.7 kJ/mol.