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Calculate the standard enthalpy change for the reduction of iron (III) oxide using carbon monoxide as the reducing agent, given that the standard enthalpy of formation for iron (III) oxide is -824.2 kJ/mol and the standard enthalpy of formation for carbon monoxide is -110.5 kJ/mol.

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To calculate the standard enthalpy change for the reduction of iron  III  oxide using carbon monoxide as the reducing agent, we first need to write a balanced chemical equation for the reaction:FeO  s  + 3CO  g   2Fe  s  + 3CO  g Next, we need to use Hess's Law, which states that the enthalpy change of a reaction is the sum of the enthalpy changes of formation of the products minus the sum of the enthalpy changes of formation of the reactants.H =  Hf  products  -  Hf  reactants We are given the standard enthalpy of formation for iron  III  oxide  FeO  and carbon monoxide  CO . We also need the standard enthalpy of formation for carbon dioxide  CO , which is -393.5 kJ/mol. The standard enthalpy of formation for elemental iron  Fe  is 0 kJ/mol since it is in its standard state.Now, we can plug the values into the equation:H = [2 0  + 3 -393.5 ] - [1 -824.2  + 3 -110.5 ]H = [-1180.5] - [-824.2 - 331.5]H = [-1180.5] - [-1155.7]H = 24.8 kJ/molThe standard enthalpy change for the reduction of iron  III  oxide using carbon monoxide as the reducing agent is 24.8 kJ/mol.

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