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What is the enthalpy change for the reduction of iron(III) oxide to iron using hydrogen gas, given that the reaction produces 2 moles of water and the standard enthalpy of formation for iron(III) oxide is -824 kJ/mol and for water is -286 kJ/mol?

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To calculate the enthalpy change for the reduction of iron III  oxide to iron using hydrogen gas, we first need to write the balanced chemical equation for the reaction:Fe2O3  s  + 3 H2  g   2 Fe  s  + 3 H2O  l Now, we can use Hess's Law to find the enthalpy change for the reaction. Hess's Law states that the enthalpy change for a reaction is equal to the sum of the enthalpy changes for the formation of the products minus the sum of the enthalpy changes for the formation of the reactants.H reaction  =  H products  -  H reactants In this case, the products are 2 moles of Fe and 3 moles of H2O, and the reactants are 1 mole of Fe2O3 and 3 moles of H2. The standard enthalpy of formation for Fe2O3 is -824 kJ/mol, and for H2O is -286 kJ/mol. The standard enthalpy of formation for elements in their standard state, such as Fe  s  and H2  g , is zero.H reaction  = [ 2  0  +  3  -286 ] - [ 1  -824  +  3  0 ]H reaction  = [-858] - [-824]H reaction  = -34 kJThe enthalpy change for the reduction of iron III  oxide to iron using hydrogen gas is -34 kJ.

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