0 votes
35 views
ago in Chemical thermodynamics by (310 points)
Calculate the standard enthalpy change for the fusion reaction of 1 mole of ice at 0°C to 1 mole of liquid water at 0°C. Given the standard enthalpy of fusion of water is 6.02 kJ/mol and the specific heat capacity of water is 4.18 J/(g·°C).

1 Answer

0 votes
ago by (990 points)
The standard enthalpy change for the fusion reaction of 1 mole of ice at 0C to 1 mole of liquid water at 0C can be calculated using the given standard enthalpy of fusion of water.Since the temperature remains constant at 0C during the fusion process, we do not need to consider the specific heat capacity of water in this calculation.The standard enthalpy of fusion of water is given as 6.02 kJ/mol. This value represents the energy required to convert 1 mole of ice at 0C to 1 mole of liquid water at 0C.Therefore, the standard enthalpy change for the fusion reaction of 1 mole of ice at 0C to 1 mole of liquid water at 0C is 6.02 kJ/mol.

Related questions

Welcome to Sarvan Science Q&A, where you can ask questions and receive answers from other members of the community.
...