To calculate the standard electrode potential for the given redox reaction, we need to determine the oxidation and reduction half-reactions and their respective standard reduction potentials.The given reaction is:Cu s + 2Ag+ aq Cu2+ aq + 2Ag s From the reaction, we can see that Cu s is being oxidized to Cu2+ aq and Ag+ aq is being reduced to Ag s .The standard reduction potentials are given as:E Ag+/Ag = +0.80 VE Cu2+/Cu = +0.34 VSince Cu is being oxidized, we need to reverse the Cu2+/Cu half-reaction and change the sign of its standard reduction potential:Cu s Cu2+ aq + 2e-E Cu/Cu2+ = -0.34 VNow, we can add the two half-reactions and their standard reduction potentials to find the overall standard electrode potential for the redox reaction:Cu s + 2Ag+ aq Cu2+ aq + 2Ag s E cell = E Ag+/Ag + E Cu/Cu2+ = +0.80 V + -0.34 V = +0.46 VSo, the standard electrode potential for the given redox reaction is +0.46 V.