As a text-based AI, I cannot draw the mechanism, but I can describe it for you. The reaction between ethanol CH3CH2OH and HBr hydrogen bromide is an acid-catalyzed substitution reaction, specifically an SN1 reaction. The overall reaction is:CH3CH2OH + HBr CH3CH2Br + H2OHere's the step-by-step mechanism:1. Protonation of the alcohol: The lone pair of electrons on the oxygen atom of the ethanol molecule attacks the hydrogen atom of the HBr molecule. This results in the formation of a protonated alcohol CH3CH2OH2+ and a bromide ion Br- .CH3CH2OH + HBr CH3CH2OH2+ + Br-2. Formation of the carbocation: The protonated alcohol molecule undergoes heterolysis, where the bond between the oxygen and the carbon atom breaks, and both electrons go to the oxygen atom. This results in the formation of a water molecule H2O and a carbocation intermediate CH3CH2+ .CH3CH2OH2+ CH3CH2+ + H2O3. Nucleophilic attack: The bromide ion Br- acts as a nucleophile and attacks the carbocation CH3CH2+ , forming a new bond between the carbon and the bromine atom. This results in the formation of the final product, bromoethane CH3CH2Br .CH3CH2+ + Br- CH3CH2BrThe overall mechanism involves the initial protonation of the alcohol, followed by the formation of a carbocation intermediate and the nucleophilic attack by the bromide ion. The final products are bromoethane and water.