Question

What is the concentration (in mol/L) of an HCl solution if 25.00 mL of this solution is required to neutralize 0.015 moles of NaOH in a titration?

Answer 1

To find the concentration of the HCl solution, we can use the balanced chemical equation for the neutralization reaction between HCl and NaOH:HCl  aq  + NaOH  aq   NaCl  aq  + H2O  l From the balanced equation, we can see that the mole ratio between HCl and NaOH is 1:1. This means that the moles of HCl required to neutralize the NaOH is equal to the moles of NaOH.Given that 0.015 moles of NaOH are neutralized, we also have 0.015 moles of HCl.Now, we can use the formula for concentration:Concentration  mol/L  = moles of solute / volume of solution  L First, we need to convert the volume of the HCl solution from mL to L:25.00 mL = 0.025 LNow, we can calculate the concentration of the HCl solution:Concentration  mol/L  = 0.015 moles / 0.025 L = 0.6 mol/LSo, the concentration of the HCl solution is 0.6 mol/L.