To determine the structure of the unknown organic compound, we will analyze the given information and use the NMR spectroscopy data.1. Molecular formula: C6H12O2This formula suggests that the compound may contain an ester, ether, or alcohol functional group, as well as some alkyl groups.2. NMR spectrum signals:- 1.2 ppm triplet : This signal is characteristic of a methyl group CH3 adjacent to a methylene group CH2 . The triplet splitting pattern indicates that the CH3 group is next to a carbon with two hydrogens n+1 rule .- 2.3 ppm quartet : This signal is characteristic of a methylene group CH2 adjacent to a carbonyl group C=O or an oxygen atom. The quartet splitting pattern indicates that the CH2 group is next to a carbon with three hydrogens n+1 rule .- 3.7 ppm doublet : This signal is characteristic of a methylene group CH2 adjacent to an oxygen atom, such as in ethers or esters. The doublet splitting pattern indicates that the CH2 group is next to a carbon with one hydrogen n+1 rule .Based on the molecular formula and the NMR data, we can propose the following structure for the unknown compound:CH3CH2COOCH2CH2CH3This structure is consistent with the molecular formula C6H12O2 and the NMR signals. The compound is an ester, specifically ethyl propionate.