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What is the chemical structure of the unknown compound X, which exhibits the NMR spectrum below: - a singlet at δ 1.2 ppm (integral = 3H)- a triplet at δ 1.4 ppm (integral = 2H)- a quartet at δ 2.0 ppm (integral = 2H)- a doublet at δ 2.5 ppm (integral = 3H)- a singlet at δ 7.3 ppm (integral = 1H)

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ago by (410 points)
Based on the given NMR spectrum, we can deduce the following information about the unknown compound X:1. Singlet at  1.2 ppm  integral = 3H : This signal corresponds to a methyl group  CH3  that is not adjacent to any other protons.2. Triplet at  1.4 ppm  integral = 2H : This signal corresponds to a methylene group  CH2  that is adjacent to another CH2 group.3. Quartet at  2.0 ppm  integral = 2H : This signal corresponds to a methylene group  CH2  that is adjacent to a CH3 group.4. Doublet at  2.5 ppm  integral = 3H : This signal corresponds to a methyl group  CH3  that is adjacent to a CH2 group.5. Singlet at  7.3 ppm  integral = 1H : This signal corresponds to an isolated proton, likely on a heteroatom or aromatic ring.Based on this information, the chemical structure of the unknown compound X can be deduced as follows:- The CH2 group giving a triplet  at  1.4 ppm  is adjacent to the CH2 group giving a quartet  at  2.0 ppm .- The CH3 group giving a doublet  at  2.5 ppm  is adjacent to the CH2 group giving a quartet  at  2.0 ppm .- The CH3 group giving a singlet  at  1.2 ppm  is not adjacent to any other protons.- The isolated proton  at  7.3 ppm  is likely on a heteroatom or aromatic ring.Taking all this information into account, the chemical structure of the unknown compound X can be represented as:CH3-CH2-CH2-CH CH3 -XWhere X is a heteroatom or an aromatic ring containing the isolated proton at  7.3 ppm. Further information, such as mass spectrometry data or IR spectroscopy, would be needed to determine the exact identity of X.

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