Based on the given NMR spectrum, we can deduce the following information about the unknown compound X:1. Singlet at 1.2 ppm integral = 3H : This signal corresponds to a methyl group CH3 that is not adjacent to any other protons.2. Triplet at 1.4 ppm integral = 2H : This signal corresponds to a methylene group CH2 that is adjacent to another CH2 group.3. Quartet at 2.0 ppm integral = 2H : This signal corresponds to a methylene group CH2 that is adjacent to a CH3 group.4. Doublet at 2.5 ppm integral = 3H : This signal corresponds to a methyl group CH3 that is adjacent to a CH2 group.5. Singlet at 7.3 ppm integral = 1H : This signal corresponds to an isolated proton, likely on a heteroatom or aromatic ring.Based on this information, the chemical structure of the unknown compound X can be deduced as follows:- The CH2 group giving a triplet at 1.4 ppm is adjacent to the CH2 group giving a quartet at 2.0 ppm .- The CH3 group giving a doublet at 2.5 ppm is adjacent to the CH2 group giving a quartet at 2.0 ppm .- The CH3 group giving a singlet at 1.2 ppm is not adjacent to any other protons.- The isolated proton at 7.3 ppm is likely on a heteroatom or aromatic ring.Taking all this information into account, the chemical structure of the unknown compound X can be represented as:CH3-CH2-CH2-CH CH3 -XWhere X is a heteroatom or an aromatic ring containing the isolated proton at 7.3 ppm. Further information, such as mass spectrometry data or IR spectroscopy, would be needed to determine the exact identity of X.