To calculate the magnetic moment of a transition metal complex, we can use the formula: = n n+2 * Bwhere is the magnetic moment, n is the number of unpaired electrons, and B is the Bohr magneton 9.274 x 10^-24 J/T .In the case of [Fe CN 6]3-, the complex is in a high-spin state and has three unpaired electrons n = 3 . Now, we can plug this value into the formula: = 3 3+2 * B = 3 5 * B = 15 * BNow, we can multiply by the Bohr magneton: = 15 * 9.274 x 10^-24 J/T 3.87 * 9.274 x 10^-24 J/T 3.59 x 10^-23 J/TSo, the magnetic moment of the [Fe CN 6]3- complex in a high-spin state with three unpaired electrons is approximately 3.59 x 10^-23 J/T.