0 votes
18 views
ago in Inorganic Chemistry by (2.1k points)
What is the magnetic moment of FeCl3 in a high-spin state with five unpaired electrons?

1 Answer

0 votes
ago by (1.7k points)
The magnetic moment    of a molecule can be calculated using the formula: =  n n+2   Bwhere n is the number of unpaired electrons and B is the Bohr magneton  approximately 9.274 x 10^-24 J/T .For FeCl3 in a high-spin state with five unpaired electrons, we can plug the values into the formula: =  5 5+2   B =  5 7   B =  35  BNow, we can multiply by the value of the Bohr magneton:   35  x  9.274 x 10^-24 J/T   5.92 x  9.274 x 10^-24 J/T   5.49 x 10^-23 J/TSo, the magnetic moment of FeCl3 in a high-spin state with five unpaired electrons is approximately 5.49 x 10^-23 J/T.
Welcome to Sarvan Science Q&A, where you can ask questions and receive answers from other members of the community.
...