Question

Calculate the heat of hydration for the reaction between anhydrous copper sulfate (CuSO4) and water (H2O), given that the mass of anhydrous copper sulfate used is 10 g and the temperature of the solution increases from 25°C to 35°C. The molar heat of hydration for copper sulfate pentahydrate (CuSO4.5H2O) is -90.1 kJ/mol.

Answer 1

To calculate the heat of hydration for the reaction between anhydrous copper sulfate  CuSO4  and water  H2O , we need to first determine the number of moles of CuSO4 used and then use the molar heat of hydration to find the total heat released.1. Calculate the number of moles of anhydrous CuSO4 used:The molar mass of CuSO4 = 63.5  Cu  + 32.1  S  + 4 * 16.0  O  = 159.6 g/molGiven mass of CuSO4 = 10 gNumber of moles of CuSO4 = mass / molar mass = 10 g / 159.6 g/mol = 0.0627 mol2. Calculate the heat of hydration:Molar heat of hydration for CuSO4.5H2O = -90.1 kJ/molHeat of hydration for 0.0627 mol of CuSO4 = 0.0627 mol *  -90.1 kJ/mol  = -5.65 kJThe heat of hydration for the reaction between anhydrous copper sulfate and water is -5.65 kJ.