Question

Calculate the heat of hydration of 1 mole of anhydrous copper(II) sulfate (CuSO4) when it is dissolved in water to form its hydrated form, CuSO4·5H2O. Given the following information:- Heat of solution of anhydrous CuSO4: -74.9 kJ/mol- Enthalpy change of hydration of CuSO4·5H2O: -245.1 kJ/mol

Answer 1

To calculate the heat of hydration of anhydrous copper II  sulfate  CuSO4 , we can use the following equation:Heat of hydration = Enthalpy change of hydration of CuSO45H2O - Heat of solution of anhydrous CuSO4Plugging in the given values:Heat of hydration =  -245.1 kJ/mol  -  -74.9 kJ/mol Heat of hydration = -245.1 kJ/mol + 74.9 kJ/molHeat of hydration = -170.2 kJ/molTherefore, the heat of hydration of 1 mole of anhydrous copper II  sulfate  CuSO4  when it is dissolved in water to form its hydrated form, CuSO45H2O, is -170.2 kJ/mol.