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Calculate the heat of formation of Methane (CH4), given the following enthalpy changes:- Enthalpy change of combustion of methane = -890.4 kJ mol^-1- Enthalpy change of formation of water = -285.8 kJ mol^-1- Enthalpy change of formation of carbon dioxide = -393.5 kJ mol^-1

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To calculate the heat of formation of methane  CH4 , we can use Hess's Law, which states that the total enthalpy change of a reaction is the same, regardless of the path taken. In this case, we can use the given enthalpy changes to create a reaction pathway that will allow us to calculate the heat of formation of methane.First, let's write down the combustion reaction of methane:CH4  g  + 2 O2  g   CO2  g  + 2 H2O  l   H = -890.4 kJ mol^-1Now, let's write down the formation reactions for water and carbon dioxide:H2  g  + 1/2 O2  g   H2O  l   H = -285.8 kJ mol^-1C  s  + O2  g   CO2  g   H = -393.5 kJ mol^-1We want to manipulate these reactions to find the formation reaction of methane. First, we need to reverse the combustion reaction of methane:CO2  g  + 2 H2O  l   CH4  g  + 2 O2  g   H = 890.4 kJ mol^-1Next, we need to multiply the formation reaction of water by 2 to match the number of moles of water in the reversed combustion reaction:2 [H2  g  + 1/2 O2  g   H2O  l ]  H = 2 -285.8  kJ mol^-1 = -571.6 kJ mol^-1Now, we can add the reversed combustion reaction, the formation reaction of carbon dioxide, and the multiplied formation reaction of water together:CO2  g  + 2 H2O  l   CH4  g  + 2 O2  g   H = 890.4 kJ mol^-1C  s  + O2  g   CO2  g   H = -393.5 kJ mol^-12 H2  g  + O2  g   2 H2O  l   H = -571.6 kJ mol^-1--------------------------------------------------------------C  s  + 2 H2  g   CH4  g   H = ?Now, we can sum up the enthalpy changes:H = 890.4 kJ mol^-1 - 393.5 kJ mol^-1 - 571.6 kJ mol^-1 = -74.7 kJ mol^-1Therefore, the heat of formation of methane  CH4  is -74.7 kJ mol^-1.

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