Question

Calculate the equilibrium constant at 25°C for the reaction: CO(g) + 3H2(g) ⇌ CH4(g) + H2O(g) If at equilibrium, the concentration of CO is 0.10 M, H2 is 0.20 M, CH4 is 0.015 M and H2O is 0.035 M.

Answer 1

To calculate the equilibrium constant  Kc  for the given reaction at 25C, we can use the expression:Kc = [CH4][H2O] /  [CO][H2]^3 Given the equilibrium concentrations:[CO] = 0.10 M[H2] = 0.20 M[CH4] = 0.015 M[H2O] = 0.035 MNow, we can plug these values into the Kc expression:Kc =  0.015  0.035  /   0.10  0.20 ^3 Kc =  0.015  0.035  /   0.10  0.008  Kc = 0.000525 / 0.0008Kc  0.656Therefore, the equilibrium constant  Kc  for the given reaction at 25C is approximately 0.656.