Question

Calculate the enthalpy change for the oxidation of 10 moles of carbon monoxide (CO) to carbon dioxide (CO2) using the enthalpy of formation values given below:∆Hf CO = -110.5 kJ/mol  ∆Hf CO2 = -393.5 kJ/mol

Answer 1

To calculate the enthalpy change for the oxidation of 10 moles of CO to CO2, we can use the following equation:H_reaction =  Hf_products -  Hf_reactantsThe balanced chemical equation for the oxidation of CO to CO2 is:2CO + O2  2CO2For 10 moles of CO, we have:10 moles CO   1 mole CO2 / 1 mole CO  = 10 moles CO2Now, we can calculate the enthalpy change for the reaction:H_reaction = [ 10 moles CO2  Hf CO2  -  10 moles CO  Hf CO ]H_reaction = [ 10  -393.5 kJ/mol  -  10  -110.5 kJ/mol ]H_reaction = [-3935 kJ -  -1105 kJ ]H_reaction = -2830 kJThe enthalpy change for the oxidation of 10 moles of carbon monoxide to carbon dioxide is -2830 kJ.