To calculate the bond order and bond length of the O-O bond in hydrogen peroxide H2O2 , we need to first understand its molecular structure and bonding.The Lewis structure of H2O2 is as follows: O / \ H O \ HEach oxygen atom is bonded to one hydrogen atom and one other oxygen atom. The oxygen-oxygen bond is a single bond, and each oxygen atom also has two lone pairs of electrons.Bond order is defined as the number of bonding electrons minus the number of antibonding electrons, divided by 2. In the case of H2O2, the O-O bond is a single bond, which means there are two bonding electrons and no antibonding electrons. Therefore, the bond order is:Bond order = Number of bonding electrons - Number of antibonding electrons / 2Bond order = 2 - 0 / 2Bond order = 1The bond order of the O-O bond in hydrogen peroxide is 1, which indicates a single bond.Now, let's calculate the bond length. The bond length of a molecule depends on the type of bond and the atoms involved. In general, bond lengths decrease as the bond order increases. For the O-O bond, we can refer to experimental data or use average bond lengths for single bonds between similar atoms.The average bond length for an O-O single bond is approximately 1.45 angstroms . Therefore, the bond length of the O-O bond in hydrogen peroxide H2O2 is approximately 1.45 .In summary, the bond order of the O-O bond in hydrogen peroxide H2O2 is 1, and the bond length is approximately 1.45 .