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Calculate the bond length between a hydrogen atom and an oxygen atom in an H2O molecule, given that the hydrogen-oxygen bond energy is 463 kJ/mol and the reduced mass of the two atoms is 1.6735 x 10^-27 kg.

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To calculate the bond length between a hydrogen atom and an oxygen atom in an H2O molecule, we can use the Morse potential equation, which relates the bond energy, reduced mass, and bond length. The equation is:E =  1/2  * k *  r - r0 ^2where E is the bond energy, k is the force constant, r is the bond length, and r0 is the equilibrium bond length.First, we need to convert the bond energy from kJ/mol to Joules:463 kJ/mol *  1000 J/1 kJ  *  1 mol/6.022 x 10^23 molecules  = 7.684 x 10^-19 JNext, we can calculate the force constant  k  using the reduced mass    and the vibrational frequency   :k =  *  2 *  *  ^2The vibrational frequency can be calculated using the bond energy  E  and the reduced mass   : =  1/ 2 *    * sqrt k/ We can rearrange the equation to solve for k:k =  *  2 *  *  ^2Since we know the bond energy  E  and the reduced mass   , we can substitute the values into the equation:7.684 x 10^-19 J =  1/2  * k *  r - r0 ^2Now, we need to find the equilibrium bond length  r0 . The equilibrium bond length can be found using the Morse potential equation:r0 = r - sqrt 2 * E / k We can rearrange the equation to solve for r0:r0 = r - sqrt 2 * 7.684 x 10^-19 J / k Now, we can substitute the values of E and  into the equation:r0 = r - sqrt 2 * 7.684 x 10^-19 J /  1.6735 x 10^-27 kg *  2 *  *  ^2  Unfortunately, we do not have enough information to solve for the vibrational frequency    and the bond length  r . However, we can use experimental data to find the bond length. The bond length between a hydrogen atom and an oxygen atom in an H2O molecule is approximately 0.96   angstroms  or 9.6 x 10^-11 m.
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