A student wishes to determine the power output of an electrochemical cell that utilizes a half-reaction of copper oxide reducing to copper and a half-reaction of zinc oxidizing to zinc ions. The initial concentrations of the copper and zinc ions in the cell are 1.00 M and 0.10 M, respectively. The cell operates for 60 minutes at a constant rate of 0.200 A. Given that the standard cell potential is 1.10 V, calculate the power output of the electrochemical cell.

Question

A student wishes to determine the power output of an electrochemical cell that utilizes a half-reaction of copper oxide reducing to copper and a half-reaction of zinc oxidizing to zinc ions. The initial concentrations of the copper and zinc ions in the cell are 1.00 M and 0.10 M, respectively. The cell operates for 60 minutes at a constant rate of 0.200 A. Given that the standard cell potential is

Answer 1

To calculate the power output of the electrochemical cell, we can use the formula:Power  P  = Voltage  V   Current  I We are given the standard cell potential  voltage  as 1.10 V and the current as 0.200 A. Plugging these values into the formula, we get:P = 1.10 V  0.200 AP = 0.22 W  watts The power output of the electrochemical cell is 0.22 watts.