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A solution of 0.1 M AgNO3 was electrolyzed using a current of 0.5 A for 150 seconds. If 0.15 g of silver was deposited, what is the value of the Faraday constant?

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First, we need to find the number of moles of silver deposited. The molar mass of silver  Ag  is 107.87 g/mol.moles of Ag = mass of Ag / molar mass of Agmoles of Ag = 0.15 g / 107.87 g/mol = 0.00139 molNext, we need to find the total charge passed during the electrolysis. The charge  Q  can be calculated using the formula:Q = current  I   time  t Q = 0.5 A  150 s = 75 CoulombsNow, we can find the number of electrons transferred during the electrolysis. Silver has a valency of 1, so one mole of electrons is required to deposit one mole of silver. Therefore, the number of moles of electrons transferred is equal to the number of moles of silver deposited.moles of electrons = moles of Ag = 0.00139 molFinally, we can calculate the Faraday constant  F  using the formula:F = charge  Q  / moles of electronsF = 75 C / 0.00139 mol = 53985.61 C/molThe Faraday constant is approximately 53985.61 C/mol.

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