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A student wanted to determine the Faraday constant using the electrolysis of silver nitrate solution. If a current of 2.5 amperes flowed through the solution for 2 hours and 30 minutes, and 0.508 grams of silver were deposited on the cathode, what is the value of the Faraday constant?

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To determine the Faraday constant, we can use the following formula:Faraday constant  F  =  mass of substance deposited * molar mass of substance  /  time * current * n where:- mass of substance deposited = 0.508 grams  silver - molar mass of silver  Ag  = 107.87 g/mol- time = 2 hours and 30 minutes = 2.5 hours = 9000 seconds  since 1 hour = 3600 seconds - current = 2.5 amperes- n = number of electrons involved in the redox reaction  for silver, n = 1, as the reaction is Ag+ + e-  Ag Now, we can plug in the values and solve for the Faraday constant:F =  0.508 g * 107.87 g/mol  /  9000 s * 2.5 A * 1 F =  54.79876 g/mol  /  22500 As F = 0.00243595 mol/AsTo convert this value to the more commonly used unit of coulombs per mole  C/mol , we can use the conversion factor:1 As = 1 CF = 0.00243595 mol/CF  96485 C/molTherefore, the value of the Faraday constant is approximately 96485 C/mol.

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