To calculate the percent yield of sodium chloride, we first need to determine the theoretical yield based on the limiting reactant. The balanced chemical equation for this reaction is:NaOH + HCl NaCl + HOFirst, we need to find the moles of each reactant:Moles of NaOH:2 g NaOH 1 mol NaOH / 40.00 g NaOH = 0.050 mol NaOHMoles of HCl:0.5 mol/L 0.050 L = 0.025 mol HClSince there is a 1:1 ratio between NaOH and HCl in the balanced equation, we can determine that HCl is the limiting reactant. Therefore, the theoretical yield of NaCl will be based on the moles of HCl.Moles of NaCl theoretical yield :0.025 mol HCl 1 mol NaCl / 1 mol HCl = 0.025 mol NaClNow, we need to convert the moles of NaCl to grams:Mass of NaCl theoretical yield :0.025 mol NaCl 58.44 g NaCl / 1 mol NaCl = 1.461 g NaClNow we can calculate the percent yield:Percent Yield = Actual Yield / Theoretical Yield 100Percent Yield = 1.5 g NaCl / 1.461 g NaCl 100 = 102.67%However, a percent yield greater than 100% is not possible, as it would mean that more product was formed than theoretically possible. This discrepancy could be due to experimental error or impurities in the reactants. In this case, we would report the percent yield as 100%.