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What is the solubility of calcium hydroxide (Ca(OH)2) in water at 25°C, given that the Ksp for Ca(OH)2 is 5.5 × 10^-6?

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To find the solubility of calcium hydroxide  Ca OH 2  in water at 25C, we can use the solubility product constant  Ksp  expression. The balanced chemical equation for the dissolution of Ca OH 2 in water is:Ca OH 2  s   Ca  aq  + 2OH  aq Let's denote the solubility of Ca OH 2 as s mol/L. When Ca OH 2 dissolves, it produces one Ca ion and two OH ions. Therefore, the concentration of Ca ions will be s mol/L, and the concentration of OH ions will be 2s mol/L.Now, we can write the Ksp expression:Ksp = [Ca] * [OH]^2Given that Ksp for Ca OH 2 is 5.5  10^-6, we can substitute the concentrations of the ions in terms of s:5.5  10^-6 =  s  *  2s ^2Now, we can solve for s:5.5  10^-6 = 4s^3s^3 =  5.5  10^-6  / 4s^3 = 1.375  10^-6s =  1.375  10^-6 ^1/3 s  0.0111 mol/LSo, the solubility of calcium hydroxide  Ca OH 2  in water at 25C is approximately 0.0111 mol/L.
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