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What is the solubility of calcium sulfate (CaSO4) in water at 25°C given that the Ksp of CaSO4 is 4.93 × 10^-5?

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To determine the solubility of calcium sulfate  CaSO4  in water at 25C, we can use the solubility product constant  Ksp  expression. The dissociation of CaSO4 in water can be represented as:CaSO4  s   Ca  aq  + SO  aq The Ksp expression for this reaction is:Ksp = [Ca][SO]Let the solubility of CaSO4 be represented by 's' mol/L. When CaSO4 dissolves, it produces 's' mol/L of Ca ions and 's' mol/L of SO ions. Therefore, we can substitute these concentrations into the Ksp expression:Ksp =  s  s  = sNow, we can solve for 's' using the given Ksp value:4.93  10 = sTo find 's', take the square root of both sides:s =  4.93  10 s  7.02  10 mol/LSo, the solubility of calcium sulfate  CaSO4  in water at 25C is approximately 7.02  10 mol/L.
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