To determine the solubility of calcium sulfate CaSO4 in water, we first need to write the balanced chemical equation for the dissolution of CaSO4:CaSO4 s Ca aq + SO aq From the given information, the concentration of Ca ions in a saturated solution is 4.7 x 10 mol/L. Since the stoichiometry of the reaction is 1:1, the concentration of SO ions will also be 4.7 x 10 mol/L.Now, we need to convert the molar concentration of CaSO4 into grams per liter. To do this, we first need to find the molar mass of CaSO4:Molar mass of CaSO4 = 40.08 g/mol for Ca + 32.07 g/mol for S + 4 x 16.00 g/mol for O Molar mass of CaSO4 = 40.08 + 32.07 + 64.00 = 136.15 g/molNow, we can convert the molar concentration of CaSO4 into grams per liter:Solubility of CaSO4 = 4.7 x 10 mol/L x 136.15 g/mol = 0.0064 g/LTherefore, the solubility of calcium sulfate CaSO4 in water at constant temperature and pressure is approximately 0.0064 grams per liter.