To determine the oxidation state of chromium in the compound K2CrO4, we'll first look at the oxidation states of the other elements in the compound.Potassium K has an oxidation state of +1. Since there are two potassium atoms, the total oxidation state for potassium in the compound is +2.Oxygen O has an oxidation state of -2. Since there are four oxygen atoms, the total oxidation state for oxygen in the compound is -8.Now, let's denote the oxidation state of chromium Cr as x. According to the oxidation state rules, the sum of the oxidation states of all elements in a neutral compound should be equal to zero. Therefore, we can set up the following equation: +2 + x + -8 = 0Solving for x:x - 6 = 0x = +6So, the oxidation state of chromium in the compound K2CrO4 is +6.