When methyl bromide CH3Br reacts with aqueous sodium hydroxide NaOH , a nucleophilic substitution reaction occurs. Specifically, it is an SN2 reaction substitution nucleophilic bimolecular . In this reaction, the hydroxide ion OH- from sodium hydroxide acts as a nucleophile and attacks the electrophilic carbon in methyl bromide, replacing the bromide ion Br- .The products formed in this reaction are methanol CH3OH and sodium bromide NaBr . The balanced chemical equation for this reaction is:CH3Br + NaOH CH3OH + NaBr