In this nucleophilic substitution reaction, the nucleophile is the hydroxide ion OH- from sodium hydroxide NaOH , and the electrophile is methyl bromide CH3Br . The hydroxide ion will attack the electrophilic carbon in methyl bromide, replacing the bromide ion Br- . The products of this reaction are methanol CH3OH and sodium bromide NaBr . The balanced chemical equation for this reaction is:CH3Br + NaOH CH3OH + NaBr