The major product obtained when 1-bromopropane reacts with sodium ethoxide in ethanol is propene. The reaction mechanism is as follows:1. Sodium ethoxide NaOEt acts as a strong base and abstracts a -hydrogen from 1-bromopropane, forming an alkoxide ion and a bromide ion.2. The alkoxide ion undergoes an intramolecular rearrangement, leading to the formation of a double bond between the and carbons, resulting in the formation of propene.3. The bromide ion and ethanol are released as byproducts.The overall reaction can be written as:CH3CH2CH2Br + NaOEt CH3CH=CH2 + EtOH + NaBrThis type of nucleophilic substitution reaction is called an E2 Elimination, Bimolecular reaction. In an E2 reaction, the nucleophile acts as a base, abstracting a proton from the substrate, and the leaving group departs simultaneously, leading to the formation of a double bond.