The balanced equation for the oxidation of ethanol C2H5OH to ethanoic acid CH3COOH using acidified potassium dichromate K2Cr2O7 is:C2H5OH + K2Cr2O7 + 4H2SO4 CH3COOH + Cr2 SO4 3 + K2SO4 + 7H2OTo determine the number of moles of potassium dichromate required to completely oxidize 25 mL of 0.1 M ethanol, we first need to find the moles of ethanol:moles of ethanol = volume concentrationmoles of ethanol = 0.025 L 0.1 mol/Lmoles of ethanol = 0.0025 molFrom the balanced equation, we can see that 1 mole of ethanol reacts with 1 mole of potassium dichromate. Therefore, the moles of potassium dichromate required are equal to the moles of ethanol:moles of potassium dichromate = 0.0025 molSo, 0.0025 moles of potassium dichromate are required to completely oxidize 25 mL of 0.1 M ethanol.