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What is the balanced chemical equation for the oxidation of ethanol (C2H5OH) to acetic acid (CH3COOH) using potassium dichromate (K2Cr2O7) as the oxidizing agent in acidic medium?

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To balance the chemical equation for the oxidation of ethanol to acetic acid using potassium dichromate as the oxidizing agent in acidic medium, we need to follow these steps:1. Write the unbalanced equation:C2H5OH + K2Cr2O7  CH3COOH2. Balance the atoms other than hydrogen and oxygen:C2H5OH + K2Cr2O7  2CH3COOH3. Balance the oxygen atoms by adding water molecules:C2H5OH + K2Cr2O7  2CH3COOH + H2O4. Balance the hydrogen atoms by adding protons  H+ :C2H5OH + K2Cr2O7 + 4H+  2CH3COOH + H2O5. Balance the charge by adding electrons  e- :C2H5OH + K2Cr2O7 + 4H+ + 6e-  2CH3COOH + H2O6. Balance the chromium atoms by adding Cr3+ ions:C2H5OH + K2Cr2O7 + 4H+ + 6e-  2CH3COOH + H2O + 2Cr3+Now the balanced chemical equation is:C2H5OH + K2Cr2O7 + 4H+ + 6e-  2CH3COOH + H2O + 2Cr3+
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