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What is the net ionic equation of the reaction between potassium permanganate and oxalic acid in an acidic solution?

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To find the net ionic equation for the reaction between potassium permanganate  KMnO4  and oxalic acid  H2C2O4  in an acidic solution, we first need to write the balanced chemical equation and then determine the net ionic equation.Balanced chemical equation:2 KMnO4 + 5 H2C2O4 + 6 H2SO4  2 MnSO4 + 10 CO2 + 8 H2O + 6 K2SO4Now, we write the total ionic equation by breaking down all the strong electrolytes into their respective ions:2 K + 2 MnO + 5 HCO + 12 H + 6 SO  2 Mn + 2 SO + 10 CO + 8 HO + 12 K + 6 SONow, we can identify and remove the spectator ions  ions that appear on both sides of the equation :Spectator ions: 2 SO, 12 KNet ionic equation:2 MnO + 5 HCO + 12 H  2 Mn + 10 CO + 8 HOThis is the net ionic equation for the reaction between potassium permanganate and oxalic acid in an acidic solution.
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