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What is the product formed when tertiary butyl alcohol undergoes dehydration in the presence of concentrated sulfuric acid?

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When tertiary butyl alcohol  t-butanol  undergoes dehydration in the presence of concentrated sulfuric acid, it forms isobutylene  also known as 2-methylpropene  as the major product. The reaction proceeds via an E1 mechanism, where the alcohol is protonated by the sulfuric acid to form a tertiary carbocation, which then loses a proton to form the alkene. The overall reaction can be represented as:t-butanol  2-methyl-2-propanol   isobutylene  2-methylpropene  + H2O
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