The dehydration of 2-methyl-2-butanol using concentrated sulfuric acid follows an E1 Elimination Unimolecular mechanism. Here's a step-by-step breakdown of the reaction:1. Protonation: The hydroxyl group -OH of 2-methyl-2-butanol acts as a nucleophile and attacks a proton H+ from the concentrated sulfuric acid H2SO4 . This results in the formation of a good leaving group, water H2O , and a carbocation intermediate.2. Carbocation formation: The water molecule leaves, generating a carbocation at the tertiary carbon the carbon attached to three other carbons of the 2-methyl-2-butanol molecule. This carbocation is relatively stable due to the inductive effect and hyperconjugation from the three alkyl groups attached to the positively charged carbon.3. Elimination: A base HSO4- from the sulfuric acid abstracts a proton H+ from one of the adjacent carbons to the carbocation, forming a double bond between the carbocation carbon and the adjacent carbon. This step results in the formation of an alkene.The major product formed in this reaction is 2-methyl-2-butene. Since the reaction follows Zaitsev's rule, the more substituted alkene is the major product. In this case, the double bond is formed between the tertiary and secondary carbons, resulting in a more substituted and stable alkene.