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Identify the number of stereoisomers possible for the following compound: 3-chloro-2-hydroxybutanoic acid.

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To determine the number of stereoisomers for 3-chloro-2-hydroxybutanoic acid, we need to identify the chiral centers in the molecule. Chiral centers are carbon atoms that have four different groups attached to them.The structure of 3-chloro-2-hydroxybutanoic acid is as follows:CH3 - CH OH  - CH Cl  - COOHThere are two chiral centers in this molecule: the carbon with the hydroxyl group  C2  and the carbon with the chlorine atom  C3 .For each chiral center, there are two possible configurations  R and S . Since there are two chiral centers, the total number of stereoisomers is 2^n, where n is the number of chiral centers.2^2 = 4Therefore, there are 4 possible stereoisomers for 3-chloro-2-hydroxybutanoic acid.
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