2,3-dibromobutane has two chiral centers, which are carbons 2 and 3. To determine the number of stereoisomers, we can use the formula 2^n, where n is the number of chiral centers. In this case, n = 2, so there are 2^2 = 4 stereoisomers.Here are the structures of the 4 stereoisomers:1. 2R,3R -2,3-dibromobutane: H H Br H | | | |H3C-C-C-C-CH3 | | | | Br H H Br2. 2S,3S -2,3-dibromobutane: Br H H Br | | | |H3C-C-C-C-CH3 | | | | H H Br H3. 2R,3S -2,3-dibromobutane: H H Br Br | | | |H3C-C-C-C-CH3 | | | | Br H H H4. 2S,3R -2,3-dibromobutane: Br H H H | | | |H3C-C-C-C-CH3 | | | | H H Br BrThese are the four possible stereoisomers of 2,3-dibromobutane: 2R,3R -2,3-dibromobutane, 2S,3S -2,3-dibromobutane, 2R,3S -2,3-dibromobutane, and 2S,3R -2,3-dibromobutane.