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Calculate the standard enthalpy change for the following reaction: 2H2(g) + O2(g) → 2H2O(l)Given the standard enthalpies of formation for H2O (l), H2 (g) and O2 (g) are -285.8 kJ/mol, 0 kJ/mol and 0 kJ/mol, respectively.
asked
Feb 3
in
Chemical thermodynamics
by
Latonya89F54
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2.2k
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0
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1
answer
52
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Calculate the standard enthalpy change for the following reaction: [Fe(H2O)6]2+(aq) + SO4 2-(aq) → [Fe(H2O)5 SO4]-(aq) + H2O(l) given that the standard enthalpies of formation of [Fe(H2O)6]2+, [Fe(H2O)5SO4]-, and H2O are -360 kJ/mol, -950 kJ/mol, and -286 kJ/mol, respectively.
asked
Feb 3
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Chemical thermodynamics
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LillyHoskins
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1.9k
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1
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39
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Calculate the standard enthalpy change for the following reaction, given the standard enthalpies of formation:2Fe (s) + 3Cl2 (g) → 2FeCl3 (s)ΔH°f(FeCl3) = -399.4 kJ/molΔH°f(Fe) = 0 kJ/molΔH°f(Cl2) = 0 kJ/mol
asked
Feb 3
in
Chemical thermodynamics
by
EfrainAlarco
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2.2k
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0
votes
1
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36
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Calculate the standard enthalpy change for the following reaction involving solids at 298 K:Fe2O3(s) + 3CO(g) → 2Fe(s) + 3CO2(g) Given the following standard enthalpies of formation in kJ/mol: Fe2O3(s) = -825.5 Fe(s) = 0CO2(g) = -393.5 CO(g) = -110.5
asked
Feb 3
in
Chemical thermodynamics
by
ArnoldJanous
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2.1k
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0
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1
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50
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Calculate the standard enthalpy change for the following reaction involving liquids at 298 K: C2H5OH(l) + 3O2(g) → 2CO2(g) + 3H2O(l)Given the standard enthalpies of formation of C2H5OH(l), CO2(g) and H2O(l) are −277.6 kJ/mol, −393.5 kJ/mol and −285.8 kJ/mol respectively.
asked
Feb 3
in
Chemical thermodynamics
by
ArleneLeichh
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2.1k
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0
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1
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59
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Calculate the standard enthalpy change for the following reaction at 298 K:Mg(s) + 2HCl(aq) → MgCl2(aq) + H2(g)
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Feb 3
in
Quantum Chemistry
by
Cathern2110
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1
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52
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Calculate the standard enthalpy change for the following reaction at 298 K: 2NaHCO3(s) + MgCl2(aq) → MgCO3(s) + 2NaCl(aq) + H2O(l)Given the following standard enthalpies of formation: ΔHf°(NaHCO3) = -950.7 kJ/molΔHf°(MgCl2) = -641.8 kJ/molΔHf°(MgCO3) = -1128.2 kJ/molΔHf°(NaCl) = -411.2 kJ/molΔHf°(H2O) = -285.8 kJ/mol
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Feb 3
in
Chemical thermodynamics
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DeboraMccomb
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1.9k
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0
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1
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42
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Calculate the standard enthalpy change for the following reaction at 298 K using the standard enthalpies of formation:2SO2(g) + O2(g) → 2SO3(g)
asked
Feb 3
in
Chemical thermodynamics
by
GarnetFjo447
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0
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1
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58
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Calculate the standard enthalpy change for the following reaction at 25°C given the enthalpies of formation (in kJ/mol) of the compounds involved:CaCO3(s) + 2HCl(aq) → CaCl2(aq) + CO2(g) + H2O(l)Hf(CaCO3) = -1206.9 kJ/molHf(CaCl2) = -795.8 kJ/molHf(CO2) = -393.5 kJ/molHf(H2O) = -285.8 kJ/molHf(HCl) = -92.31 kJ/mol
asked
Feb 3
in
Chemical thermodynamics
by
CherylDooley
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1.7k
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0
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1
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48
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Calculate the standard enthalpy change for the following neutralization reaction where hydrochloric acid (HCl) reacts with sodium hydroxide (NaOH) to form sodium chloride (NaCl) and water (H2O).HCl(aq) + NaOH(aq) → NaCl(aq) + H2O(l)Given the following tabulated standard enthalpies of formation values: ΔHf°(HCl) = -167 kJ/mol, ΔHf°(NaOH) = -469 kJ/mol, ΔHf°(NaCl) = -411 kJ/mol, ΔHf°(H2O) = -286 kJ/mol.
asked
Feb 3
in
Chemical thermodynamics
by
GavinMott60
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1.8k
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0
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1
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49
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Calculate the standard enthalpy change for the following neutralization reaction between hydrochloric acid (HCl) and sodium hydroxide (NaOH):HCl(aq) + NaOH(aq) → NaCl(aq) + H2O(l)Given: - The standard enthalpy of formation (ΔHf°) of NaCl(aq) is -407.3 kJ/mol.- The standard enthalpy of formation (ΔHf°) of H2O(l) is -285.8 kJ/mol.- The specific heat capacity (c) of the solution is 4.18 J/g°C.- The temperature change (ΔT) during the reaction is 15°C. - The mass (m) of the solution is 50.0 g. What is the standard enthalpy change (ΔH°) for the neutralization reaction between HCl and NaOH?
asked
Feb 3
in
Chemical thermodynamics
by
AlineBacon1
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1.5k
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0
votes
1
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41
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Calculate the standard enthalpy change for the following chemical reaction involving solutions:2HNO3(aq) + Ba(OH)2(aq) → Ba(NO3)2(aq) + 2H2O(l)Given the following information:ΔHf° [HNO3(aq)] = -207.5 kJ/molΔHf° [Ba(OH)2(aq)] = -994.0 kJ/molΔHf° [Ba(NO3)2(aq)] = -537.5 kJ/mol
asked
Feb 3
in
Chemical thermodynamics
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AguedaD83620
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2.6k
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0
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1
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44
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Calculate the standard enthalpy change for the dissolution reaction of 10.0 g of NaOH(s) in 100.0 g of water at 25°C, given that the heat absorbed by the solution is 9.14 kJ. (Molar mass of NaOH = 40.00 g/mol and specific heat capacity of water = 4.18 J/g·°C)
asked
Feb 3
in
Chemical thermodynamics
by
RosettaMcinn
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1.7k
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0
votes
1
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37
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Calculate the standard enthalpy change for the dissolution of 5g of sodium chloride in 100mL of water at 25°C, given that the molar enthalpy of dissolution of NaCl is -3.9 kJ/mol.
asked
Feb 3
in
Chemical thermodynamics
by
TriciaPacker
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2.2k
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0
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1
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50
views
Calculate the standard enthalpy change for the dissolution of 5.36 g of NaOH in 100.0 mL of water, given that the molar enthalpy of dissolution for NaOH is -44.5 kJ/mol.
asked
Feb 3
in
Chemical thermodynamics
by
Eileen22S142
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1.7k
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0
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1
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28
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Calculate the standard enthalpy change for the dissolution of 5.00 g of solid sodium hydroxide (NaOH) in water, given that the molar enthalpy of dissolution of NaOH is -44.51 kJ/mol. Assume that the specific heat capacity and density of the solution are the same as pure water and that no heat is lost to the surroundings during the dissolution process.
asked
Feb 3
in
Chemical thermodynamics
by
MargotFalkin
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0
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1
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50
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Calculate the standard enthalpy change for the dissolution of 5 grams of ammonium chloride (NH4Cl) in water, given that the molar enthalpy of dissolution of NH4Cl is -340.0 kJ/mol. The molar mass of NH4Cl is 53.49 g/mol and the density of water is 1.00 g/mL.
asked
Feb 3
in
Chemical thermodynamics
by
LSCJoey08837
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2.2k
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0
votes
1
answer
59
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Calculate the standard enthalpy change for the dissolution of 3.00 moles of sodium chloride in water, given that the molar enthalpy of solution of sodium chloride is -3.88 kJ/mol.
asked
Feb 3
in
Chemical thermodynamics
by
AnjaAbt20068
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2.0k
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0
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1
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29
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Calculate the standard enthalpy change for the dissolution of 3 mol of potassium chloride (KCl) in 1000 mL of water, given that the molar enthalpy of dissolution is -17.4 kJ/mol.
asked
Feb 3
in
Chemical thermodynamics
by
IvaHaugh7017
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2.1k
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0
votes
1
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35
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Calculate the standard enthalpy change for the dissolution of 10 grams of potassium hydroxide (KOH) in 100 mL of water. Given that the molar enthalpy of dissolution of solid KOH is -57.61 kJ/mol and the density of water is 1 g/mL.
asked
Feb 3
in
Chemical thermodynamics
by
EdwardoO6191
(
2.5k
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