Recent questions in Chemistry

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Calculate the standard enthalpy change for the following reaction: Fe2O3(s) + 3CO(g) → 2Fe(s) + 3CO2(g) given the following standard enthalpy of formation values: ΔHf°[Fe2O3(s)] = -824.2 kJ/mol ΔHf°[CO(g)] = -110.5 kJ/mol ΔHf°[Fe(s)] = 0 kJ/mol ΔHf°[CO2(g)] = -393.5 kJ/mol

asked Feb 3 in Chemical thermodynamics by AdelaideYwt4 (1.6k points)

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Calculate the standard enthalpy change for the following reaction: 2NaOH(aq) + H2SO4(aq) → Na2SO4(aq) + 2H2O(l) Given the following information: - The standard enthalpy of formation of NaOH(aq) is -469.20 kJ/mol - The standard enthalpy of formation of H2SO4(aq) is -814.50 kJ/mol - The standard enthalpy of formation of Na2SO4(aq) is -1388.10 kJ/mol Note: Make sure to balance the equation and use Hess's Law if necessary.

asked Feb 3 in Chemical thermodynamics by VenusU65079 (1.8k points)

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Calculate the standard enthalpy change for the following reaction: 2H2(g) + O2(g) → 2H2O(l)Given the standard enthalpies of formation for H2O (l), H2 (g) and O2 (g) are -285.8 kJ/mol, 0 kJ/mol and 0 kJ/mol, respectively.

asked Feb 3 in Chemical thermodynamics by Latonya89F54 (2.2k points)

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Calculate the standard enthalpy change for the following reaction: [Fe(H2O)6]2+(aq) + SO4 2-(aq) → [Fe(H2O)5 SO4]-(aq) + H2O(l) given that the standard enthalpies of formation of [Fe(H2O)6]2+, [Fe(H2O)5SO4]-, and H2O are -360 kJ/mol, -950 kJ/mol, and -286 kJ/mol, respectively.

asked Feb 3 in Chemical thermodynamics by LillyHoskins (1.9k points)

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Calculate the standard enthalpy change for the following reaction, given the standard enthalpies of formation:2Fe (s) + 3Cl2 (g) → 2FeCl3 (s)ΔH°f(FeCl3) = -399.4 kJ/molΔH°f(Fe) = 0 kJ/molΔH°f(Cl2) = 0 kJ/mol

asked Feb 3 in Chemical thermodynamics by EfrainAlarco (2.2k points)

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1 answer 84 views

Calculate the standard enthalpy change for the following reaction involving solids at 298 K:Fe2O3(s) + 3CO(g) → 2Fe(s) + 3CO2(g) Given the following standard enthalpies of formation in kJ/mol: Fe2O3(s) = -825.5 Fe(s) = 0CO2(g) = -393.5 CO(g) = -110.5

asked Feb 3 in Chemical thermodynamics by ArnoldJanous (2.1k points)

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1 answer 137 views

Calculate the standard enthalpy change for the following reaction involving liquids at 298 K: C2H5OH(l) + 3O2(g) → 2CO2(g) + 3H2O(l)Given the standard enthalpies of formation of C2H5OH(l), CO2(g) and H2O(l) are −277.6 kJ/mol, −393.5 kJ/mol and −285.8 kJ/mol respectively.

asked Feb 3 in Chemical thermodynamics by ArleneLeichh (2.1k points)

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1 answer 119 views

Calculate the standard enthalpy change for the following reaction at 298 K:Mg(s) + 2HCl(aq) → MgCl2(aq) + H2(g)

asked Feb 3 in Quantum Chemistry by Cathern2110 (2.0k points)

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1 answer 138 views

Calculate the standard enthalpy change for the following reaction at 298 K: 2NaHCO3(s) + MgCl2(aq) → MgCO3(s) + 2NaCl(aq) + H2O(l)Given the following standard enthalpies of formation: ΔHf°(NaHCO3) = -950.7 kJ/molΔHf°(MgCl2) = -641.8 kJ/molΔHf°(MgCO3) = -1128.2 kJ/molΔHf°(NaCl) = -411.2 kJ/molΔHf°(H2O) = -285.8 kJ/mol

asked Feb 3 in Chemical thermodynamics by DeboraMccomb (1.9k points)

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1 answer 122 views

Calculate the standard enthalpy change for the following reaction at 298 K using the standard enthalpies of formation:2SO2(g) + O2(g) → 2SO3(g)

asked Feb 3 in Chemical thermodynamics by GarnetFjo447 (1.8k points)

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1 answer 148 views

Calculate the standard enthalpy change for the following reaction at 25°C given the enthalpies of formation (in kJ/mol) of the compounds involved:CaCO3(s) + 2HCl(aq) → CaCl2(aq) + CO2(g) + H2O(l)Hf(CaCO3) = -1206.9 kJ/molHf(CaCl2) = -795.8 kJ/molHf(CO2) = -393.5 kJ/molHf(H2O) = -285.8 kJ/molHf(HCl) = -92.31 kJ/mol

asked Feb 3 in Chemical thermodynamics by CherylDooley (1.7k points)

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1 answer 122 views

Calculate the standard enthalpy change for the following neutralization reaction where hydrochloric acid (HCl) reacts with sodium hydroxide (NaOH) to form sodium chloride (NaCl) and water (H2O).HCl(aq) + NaOH(aq) → NaCl(aq) + H2O(l)Given the following tabulated standard enthalpies of formation values: ΔHf°(HCl) = -167 kJ/mol, ΔHf°(NaOH) = -469 kJ/mol, ΔHf°(NaCl) = -411 kJ/mol, ΔHf°(H2O) = -286 kJ/mol.

asked Feb 3 in Chemical thermodynamics by GavinMott60 (1.8k points)

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Calculate the standard enthalpy change for the following neutralization reaction between hydrochloric acid (HCl) and sodium hydroxide (NaOH):HCl(aq) + NaOH(aq) → NaCl(aq) + H2O(l)Given: - The standard enthalpy of formation (ΔHf°) of NaCl(aq) is -407.3 kJ/mol.- The standard enthalpy of formation (ΔHf°) of H2O(l) is -285.8 kJ/mol.- The specific heat capacity (c) of the solution is 4.18 J/g°C.- The temperature change (ΔT) during the reaction is 15°C. - The mass (m) of the solution is 50.0 g. What is the standard enthalpy change (ΔH°) for the neutralization reaction between HCl and NaOH?

asked Feb 3 in Chemical thermodynamics by AlineBacon1 (1.5k points)

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1 answer 158 views

Calculate the standard enthalpy change for the following chemical reaction involving solutions:2HNO3(aq) + Ba(OH)2(aq) → Ba(NO3)2(aq) + 2H2O(l)Given the following information:ΔHf° [HNO3(aq)] = -207.5 kJ/molΔHf° [Ba(OH)2(aq)] = -994.0 kJ/molΔHf° [Ba(NO3)2(aq)] = -537.5 kJ/mol

asked Feb 3 in Chemical thermodynamics by AguedaD83620 (2.6k points)

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1 answer 118 views

Calculate the standard enthalpy change for the dissolution reaction of 10.0 g of NaOH(s) in 100.0 g of water at 25°C, given that the heat absorbed by the solution is 9.14 kJ. (Molar mass of NaOH = 40.00 g/mol and specific heat capacity of water = 4.18 J/g·°C)

asked Feb 3 in Chemical thermodynamics by RosettaMcinn (1.7k points)

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1 answer 146 views

Calculate the standard enthalpy change for the dissolution of 5g of sodium chloride in 100mL of water at 25°C, given that the molar enthalpy of dissolution of NaCl is -3.9 kJ/mol.

asked Feb 3 in Chemical thermodynamics by TriciaPacker (2.2k points)

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1 answer 132 views

Calculate the standard enthalpy change for the dissolution of 5.36 g of NaOH in 100.0 mL of water, given that the molar enthalpy of dissolution for NaOH is -44.5 kJ/mol.

asked Feb 3 in Chemical thermodynamics by Eileen22S142 (1.7k points)

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1 answer 80 views

Calculate the standard enthalpy change for the dissolution of 5.00 g of solid sodium hydroxide (NaOH) in water, given that the molar enthalpy of dissolution of NaOH is -44.51 kJ/mol. Assume that the specific heat capacity and density of the solution are the same as pure water and that no heat is lost to the surroundings during the dissolution process.

asked Feb 3 in Chemical thermodynamics by MargotFalkin (2.1k points)

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Calculate the standard enthalpy change for the dissolution of 5 grams of ammonium chloride (NH4Cl) in water, given that the molar enthalpy of dissolution of NH4Cl is -340.0 kJ/mol. The molar mass of NH4Cl is 53.49 g/mol and the density of water is 1.00 g/mL.

asked Feb 3 in Chemical thermodynamics by LSCJoey08837 (2.2k points)

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1 answer 126 views

Calculate the standard enthalpy change for the dissolution of 3.00 moles of sodium chloride in water, given that the molar enthalpy of solution of sodium chloride is -3.88 kJ/mol.

asked Feb 3 in Chemical thermodynamics by AnjaAbt20068 (2.0k points)

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