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Recent questions in Chemistry
0
votes
1
answer
56
views
Calculate the enthalpy change for the reaction: 2H2S(g) + 3O2(g) → 2H2O(g) + 2SO2(g) given the enthalpies of formation of H2O(g), SO2(g), and H2S(g) are -241.8 kJ/mol, -296.8 kJ/mol, and -20.2 kJ/mol, respectively.
asked
Jan 23
in
ThermoChemistry
by
RhysAltman92
(
190
points)
0
votes
1
answer
53
views
Calculate the enthalpy change for the reaction: 2H2(g) + O2(g) → 2H2O(l)given that the enthalpy change of formation for water (H2O) is -285.8 kJ/mol.
asked
Jan 23
in
Chemical thermodynamics
by
HelenaGass02
(
250
points)
0
votes
1
answer
62
views
Calculate the enthalpy change for the reaction: 2H2(g) + O2(g) → 2H2O(l) using Hess's law given the following reactions: 2H2(g) + O2(g) → 2H2O(g) ΔH1 = -483.6 kJ/mol 2H2O(g) → 2H2O(l) ΔH2 = -40.7 kJ/mol
asked
Jan 23
in
ThermoChemistry
by
BryceWhittel
(
310
points)
0
votes
1
answer
67
views
Calculate the enthalpy change for the reaction: 2H₂(g) + O₂(g) → 2H₂O(g) The enthalpy of formation of H₂O is -242 kJ/mol, and the enthalpy of formation of O₂ is 0 kJ/mol.
asked
Jan 23
in
ThermoChemistry
by
RosariaLomba
(
470
points)
0
votes
1
answer
63
views
Calculate the enthalpy change for the reaction: 2H2(g) + O2(g) --> 2H2O(g) given the following enthalpy changes: H2(g) + 1/2O2(g) --> H2O(g) ΔH1 = -286 kJ/molH2(g) + 1/2Cl2(g) --> HCl(g) ΔH2 = -92 kJ/mol Cl2(g) --> 2Cl(g) ΔH3 = +242 kJ/molHCl(g) + 1/2O2(g) --> H2O(g) + Cl2(g) ΔH4 = -184 kJ/mol
asked
Jan 23
in
Chemical reactions
by
LaureneLeves
(
350
points)
0
votes
1
answer
39
views
Calculate the enthalpy change for the reaction: 2H2O(l) → 2H2(g) + O2(g) given the following bond enthalpies: H-H (436 kJ/mol), O=O (498 kJ/mol), H-O (463 kJ/mol). Is the reaction exothermic or endothermic?
asked
Jan 23
in
Chemical thermodynamics
by
ToddMcdowell
(
370
points)
0
votes
1
answer
59
views
Calculate the enthalpy change for the reaction: 2H2 (g) + O2 (g) → 2H2O (l) given that the standard enthalpy of formation for water is -285.8 kJ/mol, and standard enthalpies of formation of H2 (g) and O2 (g) are 0 kJ/mol.
asked
Jan 23
in
Chemical thermodynamics
by
ZaneSeiler9
(
350
points)
0
votes
1
answer
50
views
Calculate the enthalpy change for the reaction of burning 1 mole of methane using Hess's Law, given the following information:1) Enthalpy of formation for methane = -74.8 kJ/mol2) Enthalpy of combustion for methane = -890.3 kJ/mol3) Enthalpy of formation for water = -285.8 kJ/mol4) Enthalpy of formation for carbon dioxide = -393.5 kJ/mol
asked
Jan 23
in
ThermoChemistry
by
LaraeWicks2
(
270
points)
0
votes
1
answer
56
views
Calculate the enthalpy change for the reaction of 2.5 g of hydrogen gas with excess oxygen gas to produce water, given that the enthalpy of formation of water is -285.83 kJ/mol and the molar mass of hydrogen gas is 2.02 g/mol.
asked
Jan 23
in
ThermoChemistry
by
RosalindTarl
(
370
points)
0
votes
1
answer
60
views
Calculate the enthalpy change for the reaction below using the given bond dissociation energies:2HBr (g) + Cl2 (g) -> 2HCl (g) + Br2 (g)Bond dissociation energies:H-H = 436 kJ/molBr-Br = 193 kJ/molH-Br = 366 kJ/molCl-Cl = 242 kJ/molH-Cl = 431 kJ/mol
asked
Jan 23
in
Chemical reactions
by
QJCStuart42
(
610
points)
0
votes
1
answer
54
views
Calculate the enthalpy change for the reaction below using Hess's Law: 2CO(g) + O2(g) -> 2CO2(g), delta H = -566 kJ/mol Given the following reactions and their corresponding enthalpy changes: CO(g) + 1/2O2(g) -> CO2(g), delta H = -283 kJ/molC(s) + O2(g) -> CO2(g), delta H = -393.5 kJ/mol
asked
Jan 23
in
ThermoChemistry
by
ShelleyC9050
(
430
points)
0
votes
1
answer
76
views
Calculate the enthalpy change for the reaction below using Hess's Law and the given thermochemical equations:2H2(g) + O2(g) -> 2H2O(g) deltaH1 = -484 kJ/molH2(g) + 1/2O2(g) -> H2O(g) deltaH2 = -242 kJ/mol 2H2O(g) -> 2H2(g) + O2(g) deltaH3 = +484 kJ/mol
asked
Jan 23
in
ThermoChemistry
by
AmosDeBernal
(
510
points)
0
votes
1
answer
50
views
Calculate the enthalpy change for the process of desorption of carbon dioxide from a zeolite adsorbent at a temperature of 298 K, given that the heat of adsorption for carbon dioxide on the same zeolite at the same temperature is -40 kJ/mol.
asked
Jan 23
in
ThermoChemistry
by
878041975522
(
270
points)
0
votes
1
answer
55
views
Calculate the enthalpy change for the precipitation reaction that occurs when 50.0 mL of 0.100 M AgNO3 (aq) and 25.0 mL of 0.100 M NaCl (aq) are mixed together. The final temperature of the solution is 25.0°C, and the initial temperature of both solutions was 25.0°C. The heat capacity of the solution is 4.18 J/(g °C) and the density of each solution is 1.00 g/mL. Assume that the reaction goes to completion and that the density and specific heat capacity of the resulting solution are the same as those of pure water.
asked
Jan 23
in
ThermoChemistry
by
CyrusGeogheg
(
450
points)
0
votes
1
answer
70
views
Calculate the enthalpy change for the precipitation reaction of barium chloride and sodium sulfate, given that the initial concentrations of the two solutions are 0.2 M and are mixed in a coffee cup calorimeter. The final temperature observed is 25°C and the heat capacity of the coffee cup is 10 J/°C.
asked
Jan 23
in
ThermoChemistry
by
Julio140610
(
130
points)
0
votes
1
answer
49
views
Calculate the enthalpy change for the precipitation reaction between 50.0 mL of 0.150 M silver nitrate solution and excess sodium chloride solution if the temperature change was measured to be -5.47°C. The molar mass of AgNO3 is 169.87 g/mol, and the density of the silver nitrate solution is 1.05 g/mL. The reaction is as follows: AgNO3(aq) + NaCl(aq) -> AgCl(s) + NaNO3(aq).
asked
Jan 23
in
ThermoChemistry
by
GilbertoVall
(
330
points)
0
votes
1
answer
50
views
Calculate the enthalpy change for the precipitation reaction between 25.0 mL of 0.100 M silver nitrate (AgNO3) and excess calcium chloride (CaCl2) solution at 25°C. The balanced equation for the reaction is:AgNO3(aq) + CaCl2(aq) → AgCl(s) + Ca(NO3)2(aq)Assume the density of the solutions is equal to 1.00 g/mL and the solutions have the same specific heat as water (4.18 J/g°C).
asked
Jan 23
in
ThermoChemistry
by
BudTruong728
(
570
points)
0
votes
1
answer
61
views
Calculate the enthalpy change for the polymerization reaction of ethylene to form polyethylene using the bond dissociation energies listed below: C-H bond energy = 413 kJ/mol C=C bond energy = 602 kJ/mol Assume that the polymerization reaction proceeds via breaking of the C=C bond followed by formation of the C-C bond in polyethylene.
asked
Jan 23
in
ThermoChemistry
by
MarshaReiss
(
330
points)
0
votes
1
answer
53
views
Calculate the enthalpy change for the polymerization of propylene to polypropylene, given the enthalpy of formation of propylene is -103.8 kJ/mol and the enthalpy of formation of polypropylene is -45.4 kJ/mol. Assume the reaction occurs at constant pressure and temperature.
asked
Jan 23
in
ThermoChemistry
by
Phillis17Z51
(
310
points)
0
votes
1
answer
59
views
Calculate the enthalpy change for the polymerization of polyethylene using the following information: ΔHf° of ethylene (-20.4 kJ/mol) and polyethylene (-1024 kJ/mol); the reaction equation: nC2H4 (g) → [-CH2-CH2-]n (s)
asked
Jan 23
in
ThermoChemistry
by
JerrellBodin
(
250
points)
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