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Calculate the standard enthalpy change for the formation of methane gas (CH4) from its elements carbon (solid, graphite) and hydrogen gas (H2) given the following data:ΔHf° (C(graphite)) = 0 kJ/molΔHf° (H2(g)) = 0 kJ/molΔHc° (CH4(g)) = -890.4 kJ/mol

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To calculate the standard enthalpy change for the formation of methane gas  CH4  from its elements, we can use the following equation:Hf  CH4  =  Hf  products  -  Hf  reactants The balanced chemical equation for the formation of methane is:C graphite  + 2H2 g   CH4 g Now, we can plug in the given values:Hf  CH4  = [Hf  CH4 ] - [Hf  C graphite   + 2 * Hf  H2 g  ]Since Hf  C graphite   and Hf  H2 g   are both 0 kJ/mol, the equation simplifies to:Hf  CH4  = [Hf  CH4 ] - [0 + 2 * 0]We are given the value of Hc  CH4  which is -890.4 kJ/mol. The enthalpy of combustion  Hc  is the enthalpy change when one mole of a substance is completely burned in oxygen. In this case, we are given the enthalpy of combustion for methane, which is the reverse reaction of the formation of methane.The enthalpy change for the reverse reaction is the negative of the enthalpy change for the forward reaction. Therefore, the enthalpy change for the formation of methane  Hf  CH4   is the negative of the enthalpy of combustion  Hc  CH4  :Hf  CH4  = - -890.4 kJ/mol  = 890.4 kJ/molSo, the standard enthalpy change for the formation of methane gas  CH4  from its elements is 890.4 kJ/mol.

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