To calculate the yield of 4-bromoacetanilide, we first need to determine the theoretical yield based on the stoichiometry of the reaction and then account for the 92% purity of the final product.1. Calculate the moles of acetanilide:The molecular weight of acetanilide C8H9NO is: 12.01 * 8 + 1.01 * 9 + 14.01 + 16.00 = 135.17 g/molMoles of acetanilide = mass / molecular weightMoles of acetanilide = 10 g / 135.17 g/mol = 0.0740 mol2. Determine the moles of 4-bromoacetanilide produced:Since the reaction has 100% conversion, the moles of 4-bromoacetanilide produced is equal to the moles of acetanilide used:Moles of 4-bromoacetanilide = 0.0740 mol3. Calculate the mass of the theoretical yield of 4-bromoacetanilide:The molecular weight of 4-bromoacetanilide C8H8BrNO is: 12.01 * 8 + 1.01 * 8 + 79.90 + 14.01 + 16.00 = 214.07 g/molMass of theoretical yield = moles * molecular weightMass of theoretical yield = 0.0740 mol * 214.07 g/mol = 15.84 g4. Calculate the actual yield based on the 92% purity of the final product:Actual yield = theoretical yield * purityActual yield = 15.84 g * 0.92 = 14.57 gTherefore, the yield of 4-bromoacetanilide that can be obtained through the reaction is 14.57 grams.