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What is the thickness of a monolayer of gas adsorbed on the surface of a solid using the BET theory if the specific surface area of the solid is 100 m²/g and the volume of gas adsorbed at standard pressure is 10 mL/g?

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To calculate the thickness of a monolayer of gas adsorbed on the surface of a solid using the BET theory, we need to know the specific surface area of the solid, the volume of gas adsorbed at standard pressure, and the cross-sectional area of the adsorbed gas molecule.Given:Specific surface area  A  = 100 m/gVolume of gas adsorbed  V  = 10 mL/g = 0.01 L/g  converted to liters We also need to know the cross-sectional area of the adsorbed gas molecule. For simplicity, let's assume the gas is nitrogen  N2 , which is commonly used in BET experiments. The cross-sectional area of a nitrogen molecule    is approximately 0.162 nm.First, we need to find the number of moles of gas adsorbed per gram of solid. We can use the ideal gas law for this:PV = nRTWhere:P = pressure  1 atm, standard pressure V = volume of gas adsorbed  0.01 L/g n = number of moles of gasR = ideal gas constant  0.0821 L atm/mol K T = temperature  298 K, room temperature Rearranging the equation to solve for n:n = PV / RTn =  1 atm  0.01 L/g  /  0.0821 L atm/mol K  298 K n = 0.000407 mol/gNow, we can calculate the number of gas molecules adsorbed per gram of solid  N :N = n  Avogadro's numberN = 0.000407 mol/g  6.022  10 molecules/molN = 2.45  10 molecules/gNext, we can find the total surface area occupied by the adsorbed gas molecules  S :S = N  S = 2.45  10 molecules/g  0.162 nm/moleculeS = 3.97  10 nm/gNow, we can calculate the thickness of the monolayer  t  using the specific surface area  A  and the total surface area occupied by the adsorbed gas molecules  S :t = S / At =  3.97  10 nm/g  /  100 m/g  10 nm/m   converted m to nm t = 3.97 nmSo, the thickness of a monolayer of gas adsorbed on the surface of the solid using the BET theory is approximately 3.97 nm.

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