To calculate the theoretical yield of p-nitroaniline, we need to first determine the limiting reactant in the reaction. The balanced chemical equation for the reaction is:C6H7N + HNO3 C6H6N2O2 + H2OAniline C6H7N has a molar mass of 93.13 g/mol, and nitric acid HNO3 has a molar mass of 63.01 g/mol.First, we need to convert the given masses of reactants to moles:moles of aniline = 5 g / 93.13 g/mol = 0.0537 molmoles of nitric acid = 10 g / 63.01 g/mol = 0.1587 molNow, we need to determine the mole ratio of the reactants:mole ratio = moles of aniline / moles of nitric acid = 0.0537 / 0.1587 = 0.338The stoichiometry of the balanced equation indicates that 1 mole of aniline reacts with 1 mole of nitric acid. Since the mole ratio is less than 1, aniline is the limiting reactant.Now, we can calculate the theoretical yield of p-nitroaniline C6H6N2O2 using the stoichiometry of the balanced equation:moles of p-nitroaniline = moles of aniline = 0.0537 molThe molar mass of p-nitroaniline is 138.12 g/mol. Therefore, the theoretical yield of p-nitroaniline is:theoretical yield = 0.0537 mol 138.12 g/mol = 7.42 gSo, the theoretical yield of p-nitroaniline is 7.42 grams.