To calculate the theoretical yield of nylon-6,6, we first need to determine the limiting reactant in the reaction between adipic acid and hexamethylenediamine. We can do this by comparing the moles of each reactant.The molecular weight of adipic acid C6H10O4 is: 6 x 12.01 + 10 x 1.01 + 4 x 16.00 = 146.14 g/molThe molecular weight of hexamethylenediamine C6H16N2 is: 6 x 12.01 + 16 x 1.01 + 2 x 14.01 = 116.21 g/molNow, we can calculate the moles of each reactant:moles of adipic acid = 10 g / 146.14 g/mol = 0.0684 molmoles of hexamethylenediamine = 10 g / 116.21 g/mol = 0.0860 molThe stoichiometry of the reaction is 1:1, so the limiting reactant is adipic acid since it has fewer moles.Now, we can calculate the theoretical yield of nylon-6,6. The molecular weight of nylon-6,6 C12H22N2O2 is: 12 x 12.01 + 22 x 1.01 + 2 x 14.01 + 2 x 16.00 = 226.32 g/molSince the stoichiometry of the reaction is 1:1, the moles of nylon-6,6 produced will be equal to the moles of the limiting reactant, adipic acid.moles of nylon-6,6 = 0.0684 molNow, we can calculate the mass of nylon-6,6 produced:mass of nylon-6,6 = 0.0684 mol x 226.32 g/mol = 15.47 gThe theoretical yield of nylon-6,6 that can be produced from the reaction of 10 grams of adipic acid and 10 grams of hexamethylenediamine is 15.47 grams.