Question

What is the theoretical yield of AgCl produced when 50 mL of 0.1 M NaCl solution is mixed with 50 mL of 0.1 M AgNO3 solution?

Answer 1

To calculate the theoretical yield of AgCl, we first need to determine the limiting reactant. The balanced chemical equation for the reaction is:NaCl  aq  + AgNO3  aq   AgCl  s  + NaNO3  aq From the given information, we have:Volume of NaCl solution = 50 mLConcentration of NaCl solution = 0.1 MVolume of AgNO3 solution = 50 mLConcentration of AgNO3 solution = 0.1 MFirst, we need to find the moles of each reactant:Moles of NaCl = volume  concentration = 50 mL  0.1 M = 5 mmolMoles of AgNO3 = volume  concentration = 50 mL  0.1 M = 5 mmolSince the stoichiometry of the reaction is 1:1, we can see that both reactants are present in equal amounts. Therefore, neither reactant is limiting, and the reaction will go to completion.Now we can calculate the theoretical yield of AgCl:Moles of AgCl = moles of limiting reactant = 5 mmolTo convert moles of AgCl to grams, we need the molar mass of AgCl:Molar mass of AgCl = 107.87 g/mol  Ag  + 35.45 g/mol  Cl  = 143.32 g/molTheoretical yield of AgCl = moles  molar mass = 5 mmol  143.32 g/mol = 716.6 mgSo, the theoretical yield of AgCl produced in this reaction is 716.6 mg.