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What is the theoretical yield of acetylsalicylic acid that can be obtained from the reaction of 5 grams of salicylic acid and 10 mL of acetic anhydride, assuming complete reaction and 100% yield?

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To calculate the theoretical yield of acetylsalicylic acid, we first need to determine the limiting reactant in the reaction. The balanced chemical equation for the synthesis of acetylsalicylic acid is:C7H6O3  salicylic acid  + C4H6O3  acetic anhydride   C9H8O4  acetylsalicylic acid  + C2H4O2  acetic acid First, we need to find the moles of each reactant:Molar mass of salicylic acid  C7H6O3  =  7  12.01  +  6  1.01  +  3  16.00  = 138.12 g/molMoles of salicylic acid = 5 g / 138.12 g/mol = 0.0362 molThe density of acetic anhydride is approximately 1.08 g/mL, so 10 mL of acetic anhydride weighs 10 mL  1.08 g/mL = 10.8 g.Molar mass of acetic anhydride  C4H6O3  =  4  12.01  +  6  1.01  +  3  16.00  = 102.09 g/molMoles of acetic anhydride = 10.8 g / 102.09 g/mol = 0.1058 molNow, we can determine the limiting reactant by comparing the mole ratio of the reactants:Mole ratio of salicylic acid to acetic anhydride = 0.0362 mol / 0.1058 mol = 0.342Since the mole ratio is less than 1, salicylic acid is the limiting reactant.Now, we can calculate the theoretical yield of acetylsalicylic acid:Moles of acetylsalicylic acid = moles of salicylic acid = 0.0362 molMolar mass of acetylsalicylic acid  C9H8O4  =  9  12.01  +  8  1.01  +  4  16.00  = 180.16 g/molTheoretical yield of acetylsalicylic acid = 0.0362 mol  180.16 g/mol = 6.52 gSo, the theoretical yield of acetylsalicylic acid is 6.52 grams, assuming complete reaction and 100% yield.

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