To calculate the standard enthalpy change for the reaction, we first need to write the balanced chemical equation for the combustion of 2-methylpropan-2-ol:C4H10O + 6O2 4CO2 + 5H2ONext, we need to find the standard enthalpies of formation Hf for each compound involved in the reaction. The values are as follows:Hf C4H10O = -267.3 kJ/molHf O2 = 0 kJ/mol since it is an element in its standard state Hf CO2 = -393.5 kJ/molHf H2O = -285.8 kJ/molNow, we can use Hess's Law to calculate the standard enthalpy change for the reaction:H = [Hf products ] - [Hf reactants ]H = [4 -393.5 + 5 -285.8 ] - [ -267.3 + 6 0 ]H = -1574 + -1429 - -267.3 H = -3003 + 267.3H = -2735.7 kJ/molThe standard enthalpy change for the reaction of 2-methylpropan-2-ol with oxygen gas to form carbon dioxide and water at standard conditions is -2735.7 kJ/mol.